复数具有实部和虚部两部分,如2+5i就是一个复数,其中2为实部,5i为虚部;两复数相加时, 实部与实部相加, 虚部与虚部相加。两复数相减时,实部与实部相减, 虚部与虚部相减。如(2+5i)+(3-4i)=5+1i (2+5i)-(3-4i)=-1+9i ...
(1):具体代码(附注释)复数类:public class Complex { private float shibu;private float xubu;Complex(){this(0,0);} Complex(float shibu,float xubu){ this.shibu=shibu;this.xubu=xubu;} public void Add(...
public static void ComplexMinus(ComplexNumber x1,ComplexNumber x2){//实现两个复数相减,第一个数减第二个数 ComplexNumber cn = new ComplexNumber(0, 0);//将两个复数相加等于cn cn.shi = x1.shi - x2.shi...
JLabel label4=new JLabel("复数:("+cn1.toString()+")/(" +cn2.toString()+")="+cnDiv.toString());JLabel label5=new JLabel("复数:"+cn1.toString()+"的幅角为:"+angle);JPanel panel=new JPanel()...
复数的定义类型在java中是”Complex “。之后通过实参和虚残分别进行相加即可。代码如下:public Complex add(Complex realOne,Complex realTwo){ return realOne.add(realTwo);} class Complex{ int real;int imaginary;Comp...
private int b;public Complex() { this.a = 0;this.b = 0;} public Complex(int a, int b) { this.a = a;this.b = b;} public int getA() { return a;} public void setA(int a) { this.a = ...
减法: int a,b,c,d;int x,y; x=a-c; y=b-d 结果就为:xi+y 这很简单 再输出的时候要变为字符串型 这样你就可以再x后加个i 形成xi的形式了 乘法: int a,b,c,d;int x,y;x=a*d+b*c...
public static void main(String[] a) { Complex b = new Complex(2, 5);Complex c = new Complex(3, -4);System.out.println(b + "+" + c + "=" + b.add(c));System.out.println(b + "-" + c ...
Java程序:public class Test31 { public static void main(String[] args) { MyComplex m1 = new MyComplex(3.4, 8.0000002);MyComplex m2 = new MyComplex(3.4, 8.0000002);MyComplex m3 = new MyComplex(4....
代码如下:public class complie { int i,j;public complie(int i,int j)//构建一个复数类 { this.i=i;this.j=j;} complie add(complie c)//复数加法 { int l,k;l=c.i+i;k=c.j+j;return (new complie...